Given,
2x + 3y = 9 …(1)
8x – 2y = 5 …(2)

Let’s solve them with the help of elimination method. In order to do that we need cancel out any 1 of the element.

Solution :-

Multiply Eq (1) by 2 & Eq (2) by 3, we get

4x + 6y = 18 ..(3)
24x – 6y = 15 ..(4)

Now Add Eq (3) & Eq (4), we get

(4x + 6y) + (24x – 6y) = 18 + 15
28x = 33
x = 33/28 OR x = 1.17

Using the value of x = 33/28 in Eq (1), we get
2(33/28) + 3y = 9
3y = 9 – 33/14
3y = 93/14
y = 31/14 OR y = 2.21

Hence, Solved!