Given that sum of three consecutive odd numbers sum is 27

let us suppose consider an odd number as x

then its next consecutive odd number becomes x+2

the other consecutive odd number is x+4

we can write it as x+(x+2)+(x+4)=27

3x+6=27

subtract 6 from both sides

3x+6-6=27-6

3x=21

x=21/3

x=7

Now x+2=7+2=9

Now x+2=7+4=11

Therefore the numbers are 7,9,11.

• This reply was modified 3 months, 1 week ago by  Tejashwini Chettipelli.