SinA = 3/4 ( given)

We know that sin^2 A + cos^2 A = 1

(3/4)^2 + cos^2 A = 1

9/16 + cos^2 A = 1

Cos^2 A = 1 – 9/16

Cos^2 A = (16-9)/16

Cos^2 A = 7/ 16

CosA = ✅7 / 4

And

tan A = sinA / cos A

tan A = (3/4) / ( ✅7 / 4)

tan A = 3/✅7

Hence , cosA = ✅7 / 4 and tan A = 3/✅7