Activity › Discussion › Math › Algebra Equations › Reply To: Algebra Equations

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To solve the system of equations:
2x + 3y = 10 …(1)
4x – y = 5 …(2)
We can use the method of substitution or elimination. Let’s use the method of substitution.
From equation (2), we can isolate y:
y = 4x – 5
Now, substitute this value of y into equation (1):
2x + 3(4x – 5) = 10
Simplify the equation:
2x + 12x – 15 = 10
14x – 15 = 10
Add 15 to both sides:
14x = 10 + 15
14x = 25
Divide both sides by 14:
x = 25/14
Now substitute this value of x back into equation (2) to find y:
4(25/14) – y = 5
Simplify the equation:
100/14 – y = 5
(100 – 14y)/14 = 5
Multiply both sides by 14:
100 – 14y = 70
Subtract 100 from both sides:
14y = 70 – 100
14y = 30
Divide both sides by 14:
y = 30/14
y = 15/7
Therefore, the solution to the system of equations is:
x = 25/14
y = 15/7