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Activity Discussion Math Algebra Equations Reply To: Algebra Equations

  • Mawar

    Member
    May 1, 2024 at 12:00 pm
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    To solve the system of equations:

    2x + 3y = 10 …(1)

    4x – y = 5 …(2)

    We can use the method of substitution or elimination. Let’s use the method of substitution.

    From equation (2), we can isolate y:

    y = 4x – 5

    Now, substitute this value of y into equation (1):

    2x + 3(4x – 5) = 10

    Simplify the equation:

    2x + 12x – 15 = 10

    14x – 15 = 10

    Add 15 to both sides:

    14x = 10 + 15

    14x = 25

    Divide both sides by 14:

    x = 25/14

    Now substitute this value of x back into equation (2) to find y:

    4(25/14) – y = 5

    Simplify the equation:

    100/14 – y = 5

    (100 – 14y)/14 = 5

    Multiply both sides by 14:

    100 – 14y = 70

    Subtract 100 from both sides:

    -14y = 70 – 100

    -14y = -30

    Divide both sides by -14:

    y = -30/-14

    y = 15/7

    Therefore, the solution to the system of equations is:

    x = 25/14

    y = 15/7

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