Find answers, ask questions, and connect with our
community around the world.

Activity Discussion Math Class 8 Factorisation

  • Class 8 Factorisation

    Posted by Ananya on June 23, 2023 at 6:12 pm

    Factorise the expression and divide them as directed.

    (39y^3)(50y^2 – 98) ÷ ( 26y^2)(5y+7)

    Aakash replied 1 year, 9 months ago 2 Members · 1 Reply
  • 1 Reply
  • Aakash

    Member
    June 23, 2023 at 7:06 pm

    To factorize the expression (39y^3)(50y^2 – 98) ÷ (26y^2)(5y + 7), let’s break go step by step:

    Step 1: Factorize the numerator (39y^3)(50y^2 – 98).

    • We can find out a common factor of 2 from the expression to simplify it further:
      (39y^3)(50y^2 – 98) = 2(19y^3)(50y^2 – 98)

    Step 2: Factorize the denominator (26y^2)(5y + 7).

    • The expression (26y^2)(5y + 7) is already factored as much as possible, so leave it as it is.

    Step 3: Divide the factored numerator by the factored denominator expression.

    • Dividing (2(19y^3)(50y^2 – 98)) by ((26y^2)(5y + 7)) is equivalent to multiplying the numerator by the reciprocal of the denominator:
      (2(19y^3)(50y^2 – 98)) / ((26y^2)(5y + 7))

    To simplify the expression further, let’s cancel out any common factors between the numerator and denominator. In this case, we can cancel out the common factors of 2 and y^2:

    = (2(19y^3)(25y^2 – 49)) / ((13y^2)(5y + 7))

    Now, the (2(19y^3)(25y^2 – 49)) / ((13y^2)(5y + 7)) is fully factored and simplified expression.

Log in to reply.