
Adityava Majumder
MemberForum Replies Created
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Let age of Rohit’s brother be x years.
So according to the question , Rohit’s age = twice his brother = 2x years
Sum of their ages = 24 years
=> x + 2x = 24
=> 3x = 24
=> x = 24/3 ( here we transpose the 3 being multiplied on left hand side to divide on right hand side)
=> x = 8 years
=> 2x = 8 x 2 = 16 years
So Rohit’s brother’s age is 8 years and Rohit’s age is 16 years๐
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Area of rectangle = Length x width
Given, Length = 8m , Width = 5m
So Area of rectangle = 8 x 5 (m^2)
= 40 m^2
(Note: m^2 spelt as square meters as the same unit of length is being multiplied twice)
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As per Pythagoras theorem,
the square of length of hypotenuse (3rd or non perpendicular side) = Sum of squares of two perpendicular sides.
Here let us name the two perpendicular sides as a= 5 , b=8 and the 3rd side as c (the hypotenuse)
So using Pythagoras theorem:-
c^2 = a^2 + b^2
=> c^2 = 5^2 + 8^2
=> c^2 = 25 +64
=> c^2 = 89
=> c = โ89
=> c = 9.434 (approximate) is the length of 3rd side
(note: students not having access to calculators can stop at the c = โ89 step which is also correct )๐