[Princy Yadav]

Given equations are <div>

2x+3y=9 … eq (1) and

x-y=3 …eq(2)

To solve by elimination method, we need to make coefficient of x in both the equations equal or coefficient of y in both the equations should be equal.

Suppose, we want to make the coefficient of y equal in both the equations.

We can do it by multiplying equation 2 with 3.

On multiplying eq 2 by 3, we get,

3x – 3y = 9 …eq (3)

Now, adding eq(1) and (3), we get,

2x + 3y = 9

3x – 3y = 9

We get,

5x = 18

x = 18/5

Now, x-y=3

18/5 -y = 3

y = 18/5 – 3

= (18 – 15)/5

= 3/5

Therefore, x = 18/5 and y = 3/5

</div>

[Princy Yadav]

Let radius of the circle, r= 3.5cm and<div>

π = 22/7

Circumference of the circle= 2πr

= 2 × 22/7 × 3.5

= 2 × (22/7) × (35/10)

= 2 × 11

= 22 cm

Area of the circle = πr²

= 22/7 × (3.5)²

= 22/7 × 3.5 × 3.5

= 22 × 0.5 × 3.5

= 38.5 cm²

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[Princy Yadav]

2x + 5 = 15

2x = 15 – 5

2x = 10

x = 10/2

x = 5