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Activity Discussion Math maths

• # maths

Posted by on June 26, 2023 at 11:07 am

A, B and C enter into a partnership. A invests some money at the beginning, B invests double the amount after 6 months, and C invests thrice the amount after 8 months. If the annual gain be Rs. 18,000. A’s share is?

replied 1 year ago 2 Members · 1 Reply
• ### Varun

Member
June 26, 2023 at 11:32 am
0

To solve this problem, we need to determine the share of A in the partnership’s annual gain of Rs. 18,000.

Let’s assume that A invests x amount of money at the beginning. Then, after 6 months, B invests double the amount, so B’s investment is 2x. After 8 months, C invests thrice the amount, so C’s investment is 3x.

The share of each partner is generally determined by the ratio of their investments multiplied by the time for which they invested.

Now, let’s calculate the shares of A, B, and C:

A’s share = (A’s investment Ã— A’s time) / (Total investment Ã— Total time) = (x Ã— 12) / (6x + 2x + 3x) [Total investment = A’s investment + B’s investment + C’s investment, Total time = 12 months]

Simplifying the expression, we get:

A’s share = 12x / 11x = 12 / 11

To find the value of A’s share in terms of the annual gain, we multiply A’s share by the total annual gain:

A’s share = (12 / 11) Ã— 18,000 = 32,727.27 (rounded to two decimal places)

Therefore, A’s share in the partnership’s annual gain of Rs. 18,000 is approximately Rs. 32,727.27.

So. A’s Share = Rs 32727.

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