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Activity Discussion Math Sequence

  • Prateek

    January 5, 2024 at 2:32 pm
    Not Helpful

    To find the common difference (d) in an arithmetic progression (A.P.) when the sum of the first ‘n’ terms (Sn) is given, we can use the following formula:

    Sn = (n/2) * [2a + (n-1)d]

    where ‘a’ is the first term and ‘d’ is the common difference.

    In the given problem, Sn = 3n^2 + 2n.

    Substituting this into the formula, we have:

    3n^2 + 2n = (n/2) * [2a + (n-1)d]

    Simplifying further:

    3n^2 + 2n = (n/2) * [2a + nd – d]

    Now, let’s equate the coefficients of n^2 and n on both sides:

    3 = d/2

    Multiplying both sides by 2, we get:

    6 = d

    Therefore, the value of ‘d’ in the arithmetic progression is 6.

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