Member Nandini
MemberForum Replies Created
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Given :
The school librarian could buy 80 books casting Rs 90 each from the local bookseller and also given that the publisher offered her a 20% discount.
To Find:
The number of copies of Mathematics books which she could buy from the publisher for the sanctioned money.
Solution:
The cost of a Mathematics books= Rs 90
The cost of 80 Mathematics books= 80×90 = Rs 7200
The publisher offered her a 20% discount.
Then the discount on each Mathematics book= 90×(20/100)= Rs 18
Therefore after the discount cost of each book = 90-18 =Rs 72
Therefore the number of copies of Mathematics books which she could buy from the publisher for the sanctioned money = Total amount / cost of each book
=7200/72
=100
Thus the number of copies of Mathematics books is 100.
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Let q be the number of 2/3 kg pieces that are cut from a 4kg cake.
Therefore q×(2/3)kg = 4kg
q= 4×(3/2)
q=2× 3
q = 6
Therefore, six (2/3)kg pieces can be cut from a 4kg cake.
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(i) (2/4) ×5(1/4)
(2/4) × (21/4)
=42/16
=21/8
(ii) 2(3/5) × 2
=(13/5) ×2
=26/5
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The surface area of the cube=6a^2, a is the side of the cube.
The surface area of cuboid=2(lb+bh+hl), where l, b, h are the cuboid’s length, breadth and height.
The surface area of cylinder=2(pi)r(r+h), r is the radius of the circular base and h is the height of the cylinder.
The volume of Cube= a^3, a is the side of the cube.
The Volume of cuboid=lbh, where l, b, h are the cuboid’s length, breadth and height.
The Volume of the cylinder=(pi)(r^2)h, r is the radius of the circular base and h is the height of the cylinder.
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Firstly, we convert the hour into minutes
As we know that 1hr=60min
Therefore 7hr 25min=(7*60)+25=445min
3hr 45min=(3*60)+45=225 min
Now, subtracting 225min from 445min
445-225=220min
which is equal to( 3*60)+40= 3hr 40min
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Firstly, we convert the hour into minutes
As we know that 1hr=60min
Therefore 7hr 25min=(7*60)+25=445min
3hr 45min=(3*60)+45=225 min
Now, subtracting 225min from 445min
445-225=220min
which is equal to( 3*60)+40= 3hr 40min